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What If a 3D Surface Has Zero Curvature Everywhere?
Differential geometry & surfaces

What If a 3D Surface Has Zero Curvature Everywhere?

BEHIND THE WORK

What happens when a 3-dimensional mathematical surface has exactly zero mean curvature everywhere? Governed by Bonnet's isometric deformation family, this radiant architectural canopy morphs between a catenoid and a helicoid at theta = pi/4. Every single point rests in perfect saddle tension, woven by a single unbroken line with exact 0.000mm periodic closure.

Playlist: Differential Geometry & Minimal Surfaces

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THE MATHEMATICAL RULE

Base surface before path construction\text{Base surface before path construction}θ=π4,∣u∣≤2.2π,∣v∣≤1.25\theta=\frac\pi4,\quad |u|\leq2.2\pi,\quad |v|\leq1.25x=cos⁡θsinh⁡vsin⁡u+sin⁡θcosh⁡vcos⁡ux=\cos\theta\sinh v\sin u+\sin\theta\cosh v\cos uy=−cos⁡θsinh⁡vcos⁡u+sin⁡θcosh⁡vsin⁡uy=-\cos\theta\sinh v\cos u+\sin\theta\cosh v\sin uz=ucos⁡θ+vsin⁡θz=u\cos\theta+v\sin\theta
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