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How One Line Blooms an 8-Petal Lotus
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How One Line Blooms an 8-Petal Lotus

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How does a single continuous line bloom into an eight-petal lotus?

Governed by an 8:3 resonant epitrochoid where x(t) = 0.22 (11 cos t − 2.4 cos 11t/3) and y(t) = 0.22 (11 sin t − 2.4 sin 11t/3) over 0 ≤ t ≤ 6π, a single rolling point traces eight outer blossom petals while cross-threading through the core to weave an intricate inner rosette. Pure mathematical harmony creates sacred botanical geometry.

Artismathic turns equations into visual art—one function at a time.

Music: 'Eternal Garden' by Dan Henig

#MathArt #SacredGeometry #Geometry #Mandala #DigitalArt

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x(t)=0.22(11cost−2.4cos11t/3)x(t) = 0.22 (11 cos t − 2.4 cos 11t/3)y(t)=0.22(11sint−2.4sin11t/3)y(t) = 0.22 (11 sin t − 2.4 sin 11t/3)0≤t≤6π0 ≤ t ≤ 6π
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